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2y^2-31y+15=0
a = 2; b = -31; c = +15;
Δ = b2-4ac
Δ = -312-4·2·15
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*2}=\frac{2}{4} =1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*2}=\frac{60}{4} =15 $
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